Menu

Jamie Frost – Dr Frost Maths and Teaching High Achievers

June 26, 2016 - Podcast
Jamie Frost – Dr Frost Maths and Teaching High Achievers

On this episode of the Mr Barton Maths Podcast I spoke to Jamie Frost.

Jamie is a maths teacher at the high-achieving Tiffin School, and the creator of the amazing Dr Frost Maths.

When I say Tiffin is high-achieving, I really do mean, high-achieving. To put this into context, Jamie would expect around half of his bottom set Year 11s to achieve an A* grade, which just about put them on a par with our top set! But this context lead to a fascinating conversation about how to challenge these high achieving students, which I hope is something all teachers will find interesting and useful.

In a wide ranging interview, we covered the following things:

Jamie is engaging, and his approaches are carefully considered and thought-provoking. I hope you agree that this is another engaging, worthwhile listen.

Jamie’s website is: http://drfrostmaths.com/ 

On Twitter he is @DrFrostMaths

Jamie’s Big 3
1. mrbartonmaths (very kind, and I promise no money changed hands for this recommendation. Well, not much money, any way)
2. resourceaholic
3. ukmt and free past maths challenge questions

Podcast Puzzle
“Bob the Postman has 5 letters to deliver, one to each of 5 houses. How many ways are there are of Bob delivering the letters so that no one gets the correct letter?” 

Thanks so much for listening, and I really hope you enjoy the show!
Craig Barton

I am a maths teacher, currently teaching at Thornleigh Salesian College, Bolton, UK. Here are links to some of my work:
mrbartonnmaths.com
Mr Barton Maths Blog
Twitter: @mrbartonmaths
Diagnostic Questions
Mr Barton Maths Podcast
Just the Job Podcast

6 thoughts on “Jamie Frost – Dr Frost Maths and Teaching High Achievers

Matthew

Hi,

I’m trying to solve the podcast puzzle and possibly work out a formula for other numbers of houses/letters.

Firstly is the solution 44/120? Secondly is there a formula?

Kind regards

Matthew Smyth

Reply
    MrBarton

    I suggest you send Jamie a Tweet!

    Reply
    DrFrostMaths

    You went even further and worked out the probability! But yes, 44 is the answer. One Year 9 student at my school came up with a particularly good method: to divide up the 5 people into groups each of at least 2 people (which could be just one group of 5), then there’s (n-1)! ways within each group of n. This article explains the problem, as well as giving you both a term-to-term recurrence but also an awesomely simple position-to-term formula: en.wikipedia.org/wiki/Derangement

    Reply
      DrFrostMaths

      One thing to add: Reciprocate your probability then look at its decimal representation. Look familiar?

      Reply
maggie stewart

brilliant podcast. I am an advanced skills teacher..made me reflective, particularly about the quiet struggling student and teachers subject knowledge

Reply
    MrBarton

    Really pleased you enjoyed it!

    Reply

Leave a Reply to DrFrostMaths Cancel reply

Your email address will not be published. Required fields are marked *

You may use these HTML tags and attributes: <a href="" title=""> <abbr title=""> <acronym title=""> <b> <blockquote cite=""> <cite> <code> <del datetime=""> <em> <i> <q cite=""> <strike> <strong>